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Longitudinal deformation length (using ton force as loading)

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Length of deformation

¥ò= P/A, E = ¥ò/¥å= (P/A)/(¥ä/L)  
¥ä= PL / AE

¥ò = stress on the cross section, P = loading, A = cross-sectional area
E = modulus of elasticity
¥å = ¥ä/ L  
¥ä = longitudinal deformation, L = length of member

Changing loading unit.

1tonf = 1000kgf = 1000*gN = xtonf = 1000gN = g*10^(-3)MN

g : acceleration of gravity (m/s^2)

¥ä= PL / AE * g * 10^(-3)

Changing the unit of ¥ä from m to mm

¥ä= PL / AE * g

*** Âü°í¹®Çå[References] ***

NCEES, FUNDAMENTALS OF ENGINEERING SUPPLIED-REFERENCE HANDBOOK, 4th edition
¥ä = P*L / (A*E) * g
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