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Area of triangle, Using Heron's formula

ÀÛ¼ºÀÚ Uploader : ezmath ÀÛ¼ºÀÏ Upload Date: 2016-04-20º¯°æÀÏ Update Date: 2016-04-20Á¶È¸¼ö View : 381

The shape of the triangle is determined by the lengths of the sides. Therefore, the area can also be derived from the lengths of the sides. By Heron's formula:

A = (s(s-a)(s-b)(s-c))^(1/2)
where s= (a+b+c)/2 is the semiperimeter, or half of the triangle's perimeter.

Three other equivalent ways of writing Heron's formula are

A = (1/4)((a^2+b^2+c^2)^2-2(a^4+b^4+c^4))^(1/2)
A = (1/4)(2(a^2b^2+a^2c^2+b^2c^2)-(a^4+b^4+c^4))^(1/2)
A = (1/4)((a+b-c)(a-b+c)(-a+b+c)(a+b+c))^(1/2)

*** Âü°í¹®Çå[References] ***

https://en.wikipedia.org/wiki/Triangle
A = (((a+b+c)/2)*((a+b+c)/2-a)*((a+b+c)/2-b)*((a+b+c)/2-c))^(1/2)
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