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Area of triangle, using base line length and three angles

ÀÛ¼ºÀÚ Uploader : ezmath ÀÛ¼ºÀÏ Upload Date: 2016-04-21º¯°æÀÏ Update Date: 2016-04-21Á¶È¸¼ö View : 565

From a/sin¥á = b/sin¥â = c/sin¥ã,
a = c*sin¥á/sin¥ã. Thus h = a*sin¥â= c*sin¥á*sin¥â/sin¥ã

A = (1/2)*c*h = (1/2)(c*c*sin¥á*sin¥â/sin¥ã)

c : Base line length
¥á,¥â,¥ã : angle

*** Âü°í¹®Çå[References] ***

https://en.wikipedia.org/wiki/Triangle
A = (1/2)*(c*c*sin(¥á)*sin(¥â)/sin(¥ã))
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