Architecture
°ÇÃà Architecture


Building Pyramid - number of elements to build a pyramid (triangular base)

ÀÛ¼ºÀÚ Uploader : pleiades ÀÛ¼ºÀÏ Upload Date: 2018-08-16º¯°æÀÏ Update Date: 2018-08-16Á¶È¸¼ö View : 306

Number of elements to build a pyramid
having a triangular base is calculated as follows:

Let the number of stories from top to bottom of the pyramid as "n".

On the first story, i.e. on the top, only one element lies.
On nth story, i.e. on the bottom, the number of elements is "1+2+3+  ¡¦ + n = n(n+1)/2".

Thus, the total number of elements through all stories is:

Sum = ¢²(1/2)*(n^2 + n) = (1/2)*(¢²n^2 + ¢²n)
     = (1/2)*(n(n+1)(2n+1)/6 + n(n+1)/2)
     = (1/4)*( n(n+1)(2n+1)/3 + n(n+1) )


*** Âü°í¹®Çå[References] ***

https://en.wikipedia.org/wiki/Square_pyramidal_number
Sum = (1/4)*( n*(n+1)(2*n+1)/3 + n*(n+1) )
ÀÛ¼ºÀÚÀÇ ¼ö½Ä±×¸²ÀÌ ¾ø½À´Ï´Ù. No picture for this formula
º¯¼ö¸í Variable º¯¼ö°ª Value º¯ ¼ö ¼³ ¸í Description of the variable


¡Ø ÀÌ »çÀÌÆ®´Â ±¤°í¼öÀÍÀ¸·Î ¿î¿µµË´Ï´Ù.

¡Ú ·Î±×ÀÎ ÈÄ ¼ö½ÄÀÛ¼º ¹× Áñ°Üã±â¿¡ Ãß°¡ÇÒ ¼ö ÀÖ½À´Ï´Ù.
¡Ú To make new formula or to add this formula in your bookmark, log on please.


ÄÚ¸àÆ®

´ñ±Û ÀÔ·Â