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Minimum velocity required to revolve inside a circular track in vertical plane (at the bottom)

ÀÛ¼ºÀÚ Uploader : atom ÀÛ¼ºÀÏ Upload Date: 2018-08-22º¯°æÀÏ Update Date: 2018-08-31Á¶È¸¼ö View : 484

Minimum velocity Vb (m/s) at the bottom required to revolve inside a circular track of radius R (m) in vertical plane shown in the figure is calculated as below. 

At the top, gravity force is equal to the centrifugal force, then; 

Letting the velocity at the top as Vt,

m*g = (m*Vt^2)/R 
Vt = (R*g)^(1/2) 


By the energy conservation law, Vb is calculated as below.

(1/2)*m*Vb^2 = 2*R*m*g + (1/2)*m*Vt^2

Vb^2 = 4*R*g + Vt^2 = 4*R*g + R*g = 5*R*g

Vb = (5*R*g)^(1/2)


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Vb = (5*R*g)^(1/2)
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