1st Step for All

Science
천문학 Astronomy

생물학 Biology

화학 Chemistry

지질학 Geology

수학 Mathematics

물리 Physics

Engineering
항공우주 Aerospace

농업 Agriculture

생물 Biological

화학 Chemical

토목공학 Civil

전기공학 Electrical

환경 Environmental

산업 Industrial

해양 Marine

재료 Materials

기계 Mechanical

원자력 Nuclear

Architecture
건축 Architecture

Health
건강보건 Health

ETC
기타 ETC

현재 위치

  1. Home
  2. 물리학 Physics
  3. 고전물리학 Classical

Maximum velocity of a pendulum held at a hanging angle θ

작성자 Uploader : sunflower 작성일 Upload Date: 2018-08-29변경일 Update Date: 2018-08-29조회수 View : 1478

If the weight hanging from a rope of length L is held at an angle θ higher than the equillibrium position is released, the velocity of the weight passing the equillibrium position is maximum velocity. 
The maximum velocity can be calculated as follows: (Refer to figure) 

Potential energy = Kinetic energy 

mgH = (1/2)mV^2 
V = (2gH)^(1/2) 

Since H = L - L*cos(θ) = L(1-cos(θ)),

V = (2gL(1-cos(θ)))^(1/2)

g : acceleration of gravity (m/s^2) 
L : length of pendulum(rope) (m) 
θ : hanging angle (angle of pendulum with respect to vertical)
V : velocity of weight passing the equillibrium position (m/s) 

*** 참고문헌[References] ***
V = (2*g*L*(1-cos(θ)))^(1/2)
변수명 Variable 변수값 Value 변 수 설 명 Description of the variable


※ 이 사이트는 광고수익으로 운영됩니다.

★ 로그인 후 수식작성 및 즐겨찾기에 추가할 수 있습니다.
★ To make new formula or to add this formula in your bookmark, log on please.


코멘트

댓글 입력