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현재 위치

Height of rise of a hanging wood block hit by a bullet

작성자 Uploader : r.soi.5 작성일 Upload Date: 2018-09-11변경일 Update Date: 2018-09-12조회수 View : 334

Type1 Type2

As shown in the figure, there is an hanging object of its mass M. When a bullet hits it to the inside and moves together with it like a single object, the height of rise of the object from the initial position is calculated as follows.

1. Obtain the velocity after bullet hitting by the momentum conservation law.

2. Solve by combining the two conditions
before and after bullet hitting by the energy conservation law.

1. Velocity after collision (bullet hitting)
- By the momentum conservation law, the velocity after collision
is :
V = m*v / (m+M)
(The hanging object is stationary, thus, v2 = 0 and M*v2 = 0 in the equation below.)

2. Height of maximum rise

- kinetic energy : Ek = (1/2)(m+M)v^2
- potential energy : Ep = (m+M)gh
- Since Ek = Ep, height of rise h is obtained as follows.

Equation No.2 can be expressed as below, by using the bullet velocity v.

Equation No.2 solves h by calculating the velocity after collision,
while Equation No.3 solves h directly by the bullet velocity v.

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현재 위치

Height of rise of a hanging wood block hit by a bullet

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