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Development figureof a truncated cone (by height and radius of the circle)

ÀÛ¼ºÀÚ Uploader : goodday ÀÛ¼ºÀÏ Upload Date: 2018-09-18º¯°æÀÏ Update Date: 2018-09-19Á¶È¸¼ö View : 365

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For a truncated cone (frustum of a cone) having its bottom circle radius R, top circle radius r and height h, its development figure can be drawn as follows: No Image


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Slope length of the truncated cone, hs, is obtained by the Pythagorean Theorem.




In the development figure, the circumferences of the top and bottom circles are as below.

Cr = 2¥ðr = 2¥ðL*¥è/360  ¡æ  r = L*¥è/360
CR = 2¥ðR = 2¥ð(L+hs)*¥è/360  ¡æ  R = (L+hs)*¥è/360

Rearranging,

¥è = 360r/L = 360R/(L+hs)

thus,  r/L = R/(L+hs) 

Then, we get L and ¥è.







The central angle ¥è, length to the top circle L, and length to the bottom circle L+hs were determined as above, sothe development figure can be drawn.
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