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Calculation of angles inside a triangle, with lengths of three sides known

ÀÛ¼ºÀÚ Uploader : sunflower ÀÛ¼ºÀÏ Upload Date: 2018-09-27º¯°æÀÏ Update Date: 2018-09-28Á¶È¸¼ö View : 433

By the second law of cosine for triangles, the angle A shown in the figure can be calculated as below.

cosA = (b^2 + c^2 - a^2)/(2bc)

then,

A = arccos((b^2 + c^2 - a^2)/(2bc))

*** Âü°í¹®Çå[References] ***

http://blog.naver.com/nv_science/220783363886
A = arccos((b^2 + c^2 - a^2)/(2*b*c))
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