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Minimum circumference length of a triangle having each of its three vertices on the sides of a isosceles right triangle

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There is an isosceles right triangle (AB=BC) as shown in figure. Assuming a point P at a fixed position on the side AB, and points Q and
R at arbitrary position on the sides AC and BC respectively, the minimum circumference length of the triangle PQR is calculated as below.

By symmetric transpositions of the triangle PQR with respect
to the side AC and to the side BC, we get
three triangles in contact, as shown in figure. Then, the circumference of the triangle PQR will be the minimum when the route PP becomes a straight line.

Letting the side length of the isosceles triangle as L (=AB=BC) and length of side AP as a, the minimum circumference length, Smin, is.

Smin = (a^2 + (L+(L-a))^2)^(1/2) = (a^2 + (2*L-a)^2)^(1/2)

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Smin = (a^2 + (2*L-a)^2)^(1/2)
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