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Minimum moment M (Nm) for rotating a cylinder

ÀÛ¼ºÀÚ Uploader : ÀÚÀ¯³«ÇÏ ÀÛ¼ºÀÏ Upload Date: 2019-02-15º¯°æÀÏ Update Date: 2019-02-25Á¶È¸¼ö View : 287

As shown in the figure, a cylinder with a diameter of R (m) and a weight of W (N) is in contact with the floor and wall with friction coefficients of fb and fw, respectively. The minimum moment M (Nm) for rotating the cylinder can be obtained as follows.

Letting Rb and Rw be the frictional forces generated from the floor and the wall, respectively,and they are expressed:

Rb = (W-Rw) * fb
Rw = F * fw

Since F = Rb,

Rw = (W-Rw) * fb * fw
Rw = fb * fw * W / (1 + fb * fw).

Therefore, the minimum moment M is:

M = (Rb+Rw)*R
  = (W-Rw)*(fb+fb*fw)*R
  = W*(1-(fb*fw)/(1+fb*fw))*fb*(1+fw)*R
  = R*W*fb*(1-(fb*fw)/(1+fb*fw))*(1+fw)

*** Âü°í¹®Çå[References] ***

M = R*W*fb*(1-(fb*fw)/(1+fb*fw))*(1+fw)
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