Architecture
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The length of a train passing through tunnels and bridges of different lengths at a constant speed

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When a train running at a constant speed takes the time T1 (s) passing through a tunnel of length L1 (m) and takes the time T2 (s) passing through a bridge of length L2 (m), this train¡Çs length LT (m) can be obtained as follows.

If the speed of the train is V (m / s), the time required to pass through the tunnel and the bridge is as follows.

T1 = (L1 + LT) / V  ¡æ LT = T1 * V - L1
T2 = (L2 + LT) / V  ¡æ LT = T2 * V - L2

Solving the two together,

T1 * V - L1 = T2 * V - L2

V = (L1-L2) / (T1-T2)

And the length of the train is:

LT = T1 * (L1-L2) / (T1-T2) - L1

*** Âü°í¹®Çå[References] ***

LT = (L1-L2)*T1/(T1-T2) - L1
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