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circumference of a regular octagon in contact with the square

ÀÛ¼ºÀÚ Uploader : rainman ÀÛ¼ºÀÏ Upload Date: 2019-03-04º¯°æÀÏ Update Date: 2019-03-05Á¶È¸¼ö View : 325

The circumference of an octagon that is in contact with a square having each side length a, as shown in the figure, can be obtained as follows.

If the length of one side of the octagon is b and the length of one side of the triangle in which the square and the octagon do not overlap and if the length of a side of the triangle is c,

then, a = b + 2c.

Since the hypotenuse of the triangle has a length of 2^(1/2)*c = b,

c = b / 2^(1/2)

Substituting this into the above formula yields  a=b+2*b/sqrt(2)  and b=a/(1+2^(1/2)).

Since the circumferential length to be obtained is P = 8b,

P = 8 * (a / (1 + 2 ^ (1/2)))

*** Âü°í¹®Çå[References] ***

P = 8*(a/(1+2^(1/2)))
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