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Member force, truss type on wall, upper member

ÀÛ¼ºÀÚ Uploader : ¿ì°øÀÌ»ê ÀÛ¼ºÀÏ Upload Date: 2019-03-05º¯°æÀÏ Update Date: 2019-03-06Á¶È¸¼ö View : 337

When the forces Fx and Fy act on the point C of the structure as shown in the figure, the force FAC on the member AC is obtained as follows.

Assuming that the horizontal reaction force at point A is in the + x direction and as  the moment at point B is 0, the following equation can be made. (Clockwise: +)

Fx*(H1+H2)+Fy*L+FAC*H2*L/(L^2+H1^2)^(1/2) = 0

Thus,

FAC = -(Fx*(H1+H2)+Fy*L)*(L^2+H1^2)^(1/2) / (H2*L)

If FAC is +, the member receives a compressive force. If FAC is -, it is subjected to a tensile force.

*** Âü°í¹®Çå[References] ***

FAC = -(Fx*(H1+H2)+Fy*L)*(L^2+H1^2)^(1/2) / (H2*L)
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