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Member force, truss type on wall, lower member

ÀÛ¼ºÀÚ Uploader : ¿ì°øÀÌ»ê ÀÛ¼ºÀÏ Upload Date: 2019-03-05º¯°æÀÏ Update Date: 2019-03-06Á¶È¸¼ö View : 355

When the forces Fx and Fy act on the point C of the structure as shown in the figure, the force FBC on the member BC is obtained as follows. 

Assuming that the horizontal reaction force at point B is in the + x direction and as  the moment at point A is 0, the following equation can be made. (Clockwise: +) 

Fx*H1+Fy*L-FBC*H2*L/(L^2+(H1+H2)^2)^(1/2)

Thus,

FBC = (Fx*H1+Fy*L)*(L^2+(H1+H2)^2)^(1/2) / (H2*L)

If FBC is +, the member receives a compressive force. If FBC is -, it is subjected to a tensile force. 

*** Âü°í¹®Çå[References] ***

FBC = (Fx*H1+Fy*L)*(L^2+(H1+H2)^2)^(1/2) / (H2*L)
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