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Calculation of the drop height by the time taken to hear the sound of hitting the floor from when it is dropped

ÀÛ¼ºÀÚ Uploader : ÀÚÀ¯³«ÇÏ ÀÛ¼ºÀÏ Upload Date: 2019-06-24º¯°æÀÏ Update Date: 2019-07-15Á¶È¸¼ö View : 244

Calculate the height h (m) at which the object is dropped, if the time taken to hear the sound of hitting the floor from when it is dropped is T (s).

The distance of free falling of an object can be expressed as a function of time t (s) as follows.

h = (1/2)*g*t^2

t = (2*h/g)^(1/2)

If the speed at which sound travels in air is v (m/s), then the time ts (s) to travel h (m) is :

ts = h / v

Since the time at which sound is heard from the moment the object is dropped is T = t + ts,

T = t+ts = (2*h/g)^(1/2) + h/v

Substituting by h^(1/2) = x ,

(1/v)*x^2 + (2/g)^(1/2)*x - T = 0

Applying the root formula so that x has a positive value,

x = (v/2)*(-(2/g)^(1/2)+(2/g+4*T/v)^(1/2))

h = x^2 = (v/2)^2*(-(2/g)^(1/2)+(2/g+4*T/v)^(1/2))^2


*** Âü°í¹®Çå[References] ***

h = (v/2)^2*(-(2/g)^(1/2)+(2/g+4*T/v)^(1/2))^2
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