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Volume of two cubes; by using the sum of edge lengths and the sum of surface areas

ÀÛ¼ºÀÚ Uploader : airun ÀÛ¼ºÀÏ Upload Date: 2019-07-16º¯°æÀÏ Update Date: 2019-07-19Á¶È¸¼ö View : 294

When the sum of the lengths of the edges of two cubes is SL and the sum of the surface areas is SA, the volume SV of the two cubes is obtained as follows.

Assume the lengths of one side of two cubes are a and b, respectively, then :

12(a+b) = SL

a+b = SL/12

Squaring both sides,

a^2 + b^2 + 2*a*b = (SL/12)^2

From 6(a^2 + b^2) = SA,

a^2 + b^2 = SA/6

Then,

a*b = ((SL/12)^2 - (SA/6))/2

For the volume SV = a^3 + b^3,
applying SV = (a+b)^3 - 3*a*b*(a+b),

SV = (SL/12)^3 - 3*((SL/12)^2 - (SA/6))/2*(SL/12)



*** Âü°í¹®Çå[References] ***

SV = (SL/12)^3 - 3*((SL/12)^2 - (SA/6))/2*(SL/12)
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