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Calculation of the minimum current; serial 1& parallel 2

ÀÛ¼ºÀÚ Uploader : atom ÀÛ¼ºÀÏ Upload Date: 2019-07-26º¯°æÀÏ Update Date: 2019-08-06Á¶È¸¼ö View : 366

As shown in the figure, the minimum current in a circuit consisting of Ra and Rb = R1 + R2 can be calculated as follows.

When the total resistance Rt is maximized, the amount of current is minimized.
Rt = Ra + R1*R2/(R1+R2)

Since Rb = R1+R2, R2 = Rb-R1 applies.

Rt = Ra + R1*(Rb-R1)/(R1+(Rb-R1))
= Ra + R1*(Rb-R1)/Rb

For the maximum of R1*(Rb-R1)/Rb, assume :

y = R1*(Rb-R1)/Rb = R1 - (1/Rb)*R1^2

Then,

y¡Ç= 1 - 2/Rb*R1 = 0

Thus, when R1 = Rb/2 = R2, the current becomes the minimum.

Rt = Ra+(Rb/2)^2 / Rb = Ra+Rb/4

I = V / (Ra+Rb/4)


*** Âü°í¹®Çå[References] ***

I = V / (Ra+Rb/4)
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