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Height of liquid, when placing a horizontal cylinder (tank) vertically

ÀÛ¼ºÀÚ Uploader : ÀÏ»ó´Ù¹Ý»ç ÀÛ¼ºÀÏ Upload Date: 2019-08-15º¯°æÀÏ Update Date: 2019-08-26Á¶È¸¼ö View : 333

As shown in the figure, the length of a cylinder is L and the center angle of the ends of horizontal line of the liquid is ¥è (deg) at the center of the cylinder. When the cylinder is placed vertically, the height h of the liquid is obtained as follows.

Area of the bow-shape

S = ¥ðr^2*(¥è/360) - (1/2)*r^2*sin(¥è)

Volume of liquid

V = S*L = r^2*(¥ð*¥è/360 - (1/2)*sin(¥è))*L

For the same volume, when vertically placed,

V = ¥ð*r^2*h = r^2*(¥ð*¥è/360 - (1/2)*sin(¥è))*L

h = (¥ð*¥è/360 - (1/2)*sin(¥è))*L / ¥ð

= (L/(2*¥ð))*(¥ð*¥è/180 - sin(¥è))

*** Âü°í¹®Çå[References] ***

h = (L/(2*¥ð))*(¥ð*¥è/180 - sin(¥è))
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