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Acceleration that occurs when a force is applied horizontally to an object on a slope

ÀÛ¼ºÀÚ Uploader : Ȳ±Ý¸¶Â÷ ÀÛ¼ºÀÏ Upload Date: 2019-09-18º¯°æÀÏ Update Date: 2019-10-05Á¶È¸¼ö View : 242

As shown in the figure, when a force is applied in the horizontal direction to an object on an inclined plane having an angle of ¥è (deg) with the horizontal plane, the acceleration of the object is obtained as follows.

mass of the object : m (kg)
force applied in the horizontal direction : F(N)
friction coefficient between the inclined surface and the object : ¥ì
gravitational acceleration : g (m/s^2).

The force F applied in the horizontal direction can be divided into the force Fx in the inclined plane direction and the force Fy in the direction perpendicular to the inclined plane.

Fx = F * cos¥è
Fy = F * sin¥è

The weight of the object can be divided into the force Wx that the object goes down the slope and the force Wy that pushes the slope in a direction perpendicular to the slope.

Wx = m*g*sin¥è
Wy = m*g*cos¥è

The net force Fp that pushes the object up is given as below in consideration of the frictional force.

Fp = Fx - Wx - ¥ì(Fy+Wy)
   = F*cos¥è - m*g*sin¥è - ¥ì(F*sin¥è+m*g*cos¥è)

Therefore, the acceleration a which arises in the object can be calculated by the following formula.

a = Fp / m
  = (F*cos¥è - m*g*sin¥è - ¥ì(F*sin¥è+m*g*cos¥è)) / m

*** Âü°í¹®Çå[References] ***

a = (F*cos(¥è) - m*g*sin(¥è) - ¥ì*(F*sin(¥è)+m*g*cos(¥è))) / m
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