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Maximum allowable concentrated load; by allowable shear stress of circular cross section simple beam

ÀÛ¼ºÀÚ Uploader : milinae ÀÛ¼ºÀÏ Upload Date: 2019-09-20º¯°æÀÏ Update Date: 2019-10-06Á¶È¸¼ö View : 350

As shown in the figure, when the concentrated load acts on the center of a circular steel bar having length L (cm) and diameter D (cm), the maximum allowable concentrated load P (kgf) can be obtained as follows. The allowable shear stress of the steel bar is ¥ó (kgf/cm^2).

Shear Force: S = P / 2
Cross section: A = (¥ð / 4) * D ^ 2

Shear force : S = P/2
Cross section : A = (¥ð/4)*D^2

¥ó = (4/3)*(S/A) = (4/3)*(P/2)/((¥ð/4)*D^2) = 8*P/(3*¥ð*D^2)

P = (3/8)*(¥ð*¥ó*D^2)

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P = (3/8)*(¥ð*¥ó*D^2)
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