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Velocity when the slid object escapes from the hemisphere surface

ÀÛ¼ºÀÚ Uploader : corona ÀÛ¼ºÀÏ Upload Date: 2019-09-23º¯°æÀÏ Update Date: 2020-03-14Á¶È¸¼ö View : 254

As shown in the figure, the object at the apex of the hemisphere with a radius of R (m) starts to slide. The velocity V (m/s) at the moment of departure when the obhect escapes from the hemisphere surface by acceleration is obtained as follows. 

It is assumed that there is no friction between the hemisphere and the object. 

The velocity V of the object at the position, where the line connecting the center of the hemisphere and the object is angled at ¥è with respect to the horizontal line, is as follows. 

V = (2*g*R*(1-sin¥è))^(1/2) 

If the mass of the object is m, the centrifugal force F1 at this time is as follows. 

F1 = m*V^2/R = m*2*g*R*(1-sin¥è)/R = 2*m*g*(1-sin¥è) 

On the other hand, the centripetal force F2 toward the center of the sphere due to gravity is as follows. 

F2 = m*g*sin¥è 

At the moment F1 = F2, it starts to deviate from the surface of the hemisphere. Then, 

2*m*g*(1-sin¥è) = m*g*sin¥è 

sin¥è = 2/3 

Therefore, the velocity V is as follows.

V = (2*g*R/3)^(1/2)


*** Âü°í¹®Çå[References] ***

V = (2*g*R/3)^(1/2)
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