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Maximum allowable concentrated load; by allowable tensile stress and shear stress of circular cross section simple beam

작성자 Uploader : milinae 작성일 Upload Date: 2019-10-06변경일 Update Date: 2019-10-06조회수 View : 781

Type1 Type2
As shown in the figure, when the concentrated load acts on the center of a circular steel bar having length L (cm) and diameter D (cm), the maximum allowable concentrated load P (kgf) is can be obtained as follows. The allowable stress of the steel bar is σ (kgf /cm^2).

Maximum moment : M = P*L/4
Second moment of inertia : I = (π/64)*D^4

σ= (M/I)*(D/2) = (P*L/4)*(D/2) / ((π/64)*D^4) = 8*P*L/(π*D^3)

P1  = π*σ*D^3 / (8*L)

Shear Force: S = P / 2
Cross section: A = (π / 4) * D ^ 2

τ = (4/3)*(S/A) = (4/3)*(P/2)/((π/4)*D^2) = 8*P/(3*π*D^2)

P2 = (3/8)*(π*τ*D^2)

Select the smaller value among P1 and P2. 		No Image
▶ allowable concentrated load; by allowable tensile stress



▶ allowable concentrated load; by allowable shear stress



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