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Maximum volume of a cylinder inscribed in a cone

ÀÛ¼ºÀÚ Uploader : ¿ä¼ú·¥ÇÁ ÀÛ¼ºÀÏ Upload Date: 2019-11-09º¯°æÀÏ Update Date: 2022-06-18Á¶È¸¼ö View : 108

Find the maximum volume of a cylinder inscribed in a cone of radius R and height H.

If the radius of the cylinder is r and the height is h, then the volume V of the cylinder is:

V = ¥ð*r^2*h

Also, since H : R = h : R-r,

R*h = H*(R-r)

h = H*(R-r)/R

Thus,

V = ¥ð*r^2*H*(R-r)/R

 = (¥ð*H/R)*(R*r^2-r^3)

When R*r^2-r^3 is maximum, V becomes maximum, so if we differentiate with respect to r to find r that becomes 0,

2*R*r - 3*r^2 = 0

r*(2*R - 3*r) = 0

Since 0 < r < R, r = 2*R/3.

Therefore, the maximum volume Vmax of the cylinder is:

Vmax = (¥ð*H/R)*(R*4*R^2/9 - 8*R^3/27)

    = (4/27)*¥ð*H*R^2

*** Âü°í¹®Çå[References] ***

Vmax = (4/27)*¥ð*H*R^2
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