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현재 위치

Reaction force, center point when uniform load is applied to continuous beam

작성자 Uploader : orion 작성일 Upload Date: 2019-11-13변경일 Update Date: 2020-01-06조회수 View : 340

When the uniform distribution load w (kN / m) acts on the continuous beam as shown in the figure, the reaction forces RA, RB, RC at the points A, B, and C are obtained as follows.

Since only vertical forces act, only vertical reactions occur.

Solve using the fact that the deflection δ1 at the point B due to the uniform distribution load and the deformation δ2 due to the reaction force RB are the same.

δ1 = 5*w*(2*L)^4 / (384*E*I) = 5*w*L^4 / (24*E*I)

δ2 = RB*(2*L)^3 / (48*E*I) = RB*L^3 / (6*E*I)

RB*L^3 / (6*E*I) = 5*w*L^4 / (24*E*I)

RB = 5*w*L / 4

Since RA = RC and RA+RB+RC = w*2*L,

2RA = w*2*L - 5*w*L/4

RA = 3*w*L/8

*** 참고문헌[References] ***

RB = 5*w*L/4

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현재 위치

Reaction force, center point when uniform load is applied to continuous beam

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