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Solenoid, finding the number of turns according to the internal magnetic field strength

작성자 Uploader : atom 작성일 Upload Date: 2019-11-19변경일 Update Date: 2020-02-29조회수 View : 150

When the current I (A) flows through the solenoid having a length L (m) and the number of turns N, the strength B (T) of the magnetic field inside the solenoid can be obtained by the following equation.

B = μ*N*I/L

B : magnitude of magnetic field (N/A·m = T = Wb/m^2)
μ : magnetic constant = 4π*10^(-7) (H/m = T*m/A)
N : number of turns
I : current (A)
L : length of solenoid (m)

N = B*L/(μ*I)
   = (10^7)*B*L/(4*π*I)

*** 참고문헌[References] ***

https://en.wikipedia.org/wiki/Solenoid
N = (10^7)*B*L/(4*π*I)
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