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Finding deflection when concentrated load is applied on a simple beam, x ¡Â location of load

ÀÛ¼ºÀÚ Uploader : metalheart ÀÛ¼ºÀÏ Upload Date: 2019-11-27º¯°æÀÏ Update Date: 2019-11-29Á¶È¸¼ö View : 4415

When the concentrated load P (kN) is applied on a simple beam of length L (m) as shown in the figure, the deflection of the beam vx (mm) is obtained as follows.

For x ¡Â Lp, deflection equation is as follows.

vx = (P*x/(6*E*I*L))*(L-Lp)*(x^2 + Lp^2 - 2*L*Lp)

When the unit of E is MPa and the unit of I is cm ^ 4, the unit of vx is

(kN*m/(1000*kN/m^2*(0.01m)^4*m))*m^3 = 10^5*m

therefore, to make the unit of vx in mm, the above equation can be written as follows.

vx = (P*x/(6*E*I*L))*(L-Lp)*(x^2 + Lp^2 - 2*L*Lp)*10^8



*** Âü°í¹®Çå[References] ***

For deflection equation, refer to
http://ezformula.net/esne/aboard/view.php?bbs_id=bbs03&doc_num=145
vx = (P*x/(6*E*I*L))*(L-Lp)*(x^2 + Lp^2 - 2*L*Lp)*10^8
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