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³ôÀÌ h ¿¡¼­ ´øÁø ¹°Ã¼(Æ÷»çü, Æ÷¹°Ã¼)°¡ Áö¸é¿¡ µµ´ÞÇÒ ¶§ÀÇ ¼Ó·Â

ÀÛ¼ºÀÚ Uploader : ¾ß°£ºñÇà ÀÛ¼ºÀÏ Upload Date: 2022-04-08º¯°æÀÏ Update Date: 2022-04-08Á¶È¸¼ö View : 475

³ôÀÌ h (m) ¿¡¼­ ¼öÆò°ú ¥è (¢ª) ¸¦ ÀÌ·ç´Â ¹æÇâÀ¸·Î ¼Ó·Â v (m/s) ·Î ¹°Ã¼¸¦ ´øÁ³À» ¶§, ¹°Ã¼°¡ Áö¸é¿¡ µµ´ÞÇÏ´Â ¼ø°£ÀÇ ¼Ó·Â ve (m/s) ¸¦ ±¸ÇÑ´Ù.

¼öÁ÷¹æÇâ ¹× ¼öÆò¹æÇâ ¼Ó·Â

vx = v*cos(¥è)
vy = v*sin(¥è) - g*t

g : Á߷°¡¼Óµµ (m/s^2)
t : °É¸°½Ã°£ (sec)

¼öÁ÷¹æÇâ ¹× ¼öÆò¹æÇâ À̵¿°Å¸®

sx = v*cos(¥è)*t
sy = h + v*sin(¥è)*t - (1/2)*g*t^2

¹Ù´Ú¿¡ µµ´ÞÇÏ´Â ½Ã°£À» ±¸Çϸé, sy = 0 À̹ǷÎ,

g*t^2 - 2*v*sin(¥è)*t - 2*h = 0

t = (1/g)*(v*sin(¥è)+sqr((v*sin(¥è))^2 + 2*g*h))

ÀÌ µÈ´Ù.

À̶§ °¢ ¼ººÐÀÇ ¼Ó·ÂÀº,

vx = v*cos(¥è)
vy = v*sin(¥è) - (v*sin(¥è)+sqr((v*sin(¥è))^2 + 2*g*h)) = -sqr((v*sin(¥è))^2 + 2*g*h)

ÀÌ°í, ve = sqr(vx^2+vy^2) À̹ǷÎ,

ve = sqr((v*cos(¥è))^2 + (v*sin(¥è))^2 + 2*g*h) = sqr(v^2+2*g*h)

°¡ µÈ´Ù.

*** Âü°í¹®Çå[References] ***

ve = sqr(v^2+2*g*h)
ÀÛ¼ºÀÚÀÇ ¼ö½Ä±×¸²ÀÌ ¾ø½À´Ï´Ù. No picture for this formula
º¯¼ö¸í Variable º¯¼ö°ª Value º¯ ¼ö ¼³ ¸í Description of the variable


¡Ø ÀÌ »çÀÌÆ®´Â ±¤°í¼öÀÍÀ¸·Î ¿î¿µµË´Ï´Ù.

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  • ÀÌ°Ç ¿¡³ÊÁö½ÄÀ¸·Î Ç®¸é ±Ý¹æ ³ª¿ÀÁÒ.

    (1/2)mve^2 = (1/2)mv^2+mgh

    ve = sqr(v^2+2gh)

    ¹¹... ±×·¸´Ù±¸¿ä..

    guest7
    [2022-06-23 18:20:52]
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