Architecture
°ÇÃà Architecture


Á¤¿À°¢ÇüÀ» µÑ·¯½Ñ ¿øÈ£¸¦ Æ÷ÇÔÇÑ ¸éÀû(area of Reuleaux regular pentagon)

ÀÛ¼ºÀÚ Uploader : Àû´çÈ÷ ÀÛ¼ºÀÏ Upload Date: 2022-05-07º¯°æÀÏ Update Date: 2022-05-07Á¶È¸¼ö View : 330

±×¸²°ú °°ÀÌ ÇÑ º¯ÀÇ ±æÀÌ°¡ a ÀÎ Á¤¿À°¢Çü°ú ´ë°¢¼±À¸·Î ±×¸° ¿øÈ£·Î µÑ·¯½ÎÀÎ ¸éÀû A ¸¦ ±¸ÇÑ´Ù.

Á¤¿À°¢ÇüÀÇ ¸éÀû Ap

Ap = (1/4)*a^2*sqr(25+10*sqr(5))

¿À°¢ÇüÀÇ ³ôÀÌ h

h = (1/2)*sqr(5+2sqr(5))*a

´ë°¢¼±ÀÇ ±æÀÌ d

d = (1/2)*(1+sqr(5))*a

´ë°¢¼± »çÀÌÀÇ °¢ ¥è = 36¢ª

¿À°¢Çü°ú È£ »çÀÌÀÇ ¸éÀû Aa

Aa = ¥ð*d^2*(36/360) - (1/2)*a*h

  = ¥ð*((1/2)*(1+sqr(5))*a)^2*(36/360) - (1/2)*a*((1/2)*sqr(5+2sqr(5))*a)

  = ¥ð*(1/20)*(3+sqr(5))*a^2 - (1/4)*sqr(5+2sqr(5))*a^2

Aa °¡ n °³ ÀÖ´Ù¸é, ±¸ÇÏ°íÀÚÇÏ´Â ¸éÀû A ´Â ´ÙÀ½°ú °°´Ù.

A = Ap + n*Aa

  = (1/4)*a^2*sqr(25+10*sqr(5)) + n(¥ð*(1/20)*(3+sqr(5))*a^2 - (1/4)*sqr(5+2sqr(5))*a^2)

  = (1/4)*a^2*(sqr(25+10*sqr(5)) + n(¥ð*(1/5)*(3+sqr(5)) - sqr(5+2sqr(5))))

*** Âü°í¹®Çå[References] ***

A = (1/4)*a^2*(sqr(25+10*sqr(5)) + n*(¥ð*(1/5)*(3+sqr(5)) - sqr(5+2sqr(5))))
º¯¼ö¸í Variable º¯¼ö°ª Value º¯ ¼ö ¼³ ¸í Description of the variable


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