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ÀÛ¼ºÀÚ Uploader : Àâ¾î¸Å¿îÅÁ ÀÛ¼ºÀÏ Upload Date: 2022-05-13º¯°æÀÏ Update Date: 2022-05-13Á¶È¸¼ö View : 350

¿°µµ°¡ P (%) ÀÎ ¾×ü S (g) ¿¡ Æ÷ÇÔµÈ ³ªÆ®·ýÀÇ Áú·® mNa (g) À» ±¸ÇÑ´Ù.

¾×üÁß ¼Ò±Ý(¿°È­³ªÆ®·ý, NaCl)ÀÇ Áú·®À» m (g) À̶ó°í Çϸé,

m = (P/100)*S

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NaCl ÀÇ ¸ôÁú·®Àº 58.44 (g/mol) ÀÌ°í, Na ÀÇ ¸ôÁú·®Àº 23 (g/mol) À̹ǷÎ,

mNa = (23/58.44)*m = (23/58.44)*(P/100)*S

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*** Âü°í¹®Çå[References] ***

mNa = (23/58.44)*(P/100)*S
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