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Radius of gyration of area, hollow rectangular section

ÀÛ¼ºÀÚ Uploader : a.c.e. ÀÛ¼ºÀÏ Upload Date: 2023-06-10º¯°æÀÏ Update Date: 2023-06-10Á¶È¸¼ö View : 78

As shown in the figure, find the radius of gyration of area r (cm) of the cross section of a hollow rectangle with height h (cm), width b (cm), and thickness t (cm).

Since r = sqr(I/A), I is the second moment of area and A is the area,

I = (1/12)*(b*h^3 - (b-2*t)*(h-2*t)^3)

A = b*h - (b-2*t)*(h-2*t)

Thus,

r = sqr( (1/12)*(b*h^3 - (b-2*t)*(h-2*t)^3) / (b*h - (b-2*t)*(h-2*t)) )

*** Âü°í¹®Çå[References] ***

r = sqr( (1/12)*(b*h^3 - (b-2*t)*(h-2*t)^3) / (b*h - (b-2*t)*(h-2*t)) )
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