Architecture
°ÇÃà Architecture


Finding the initial velocity of a moving object when it stops after moving a certain distance

ÀÛ¼ºÀÚ Uploader : orion ÀÛ¼ºÀÏ Upload Date: 2023-06-11º¯°æÀÏ Update Date: 2023-06-11Á¶È¸¼ö View : 72

When an object of mass M (kg) moves at an initial velocity V (m/s), decelerates constantly in the section with a friction coefficient ¥ì with the floor, moves L (m), and then stops, the initial velocity V of the object is obtained.

¡à Acceleration : a = v^2/(2*L)
¡à The force that stops an object : F = M*a
¡à Friction force : Ff = ¥ì*M*g

The force that stops an object is equal to the friction force.

M*a = ¥ì*M*g

Thus,

a = ¥ì*g

V^2/(2*L) = ¥ì*g

V = sqr(2*¥ì*L*g)

*** Âü°í¹®Çå[References] ***

V = sqr(2*¥ì*L*g)
ÀÛ¼ºÀÚÀÇ ¼ö½Ä±×¸²ÀÌ ¾ø½À´Ï´Ù. No picture for this formula
º¯¼ö¸í Variable º¯¼ö°ª Value º¯ ¼ö ¼³ ¸í Description of the variable


¡Ø ÀÌ »çÀÌÆ®´Â ±¤°í¼öÀÍÀ¸·Î ¿î¿µµË´Ï´Ù.

¡Ú ·Î±×ÀÎ ÈÄ ¼ö½ÄÀÛ¼º ¹× Áñ°Üã±â¿¡ Ãß°¡ÇÒ ¼ö ÀÖ½À´Ï´Ù.
¡Ú To make new formula or to add this formula in your bookmark, log on please.


ÄÚ¸àÆ®

´ñ±Û ÀÔ·Â