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Thermal efficiency of thermal power plants

ÀÛ¼ºÀÚ Uploader : doturak ÀÛ¼ºÀÏ Upload Date: 2023-07-05º¯°æÀÏ Update Date: 2023-07-05Á¶È¸¼ö View : 103

When a thermal power plant produces P (kWh) of electricity and uses W (ton) of fuel with a heating value of C (kcal/kg), the thermal efficiency ¥ç (%) of the thermal power plant can be obtained as follows.

Total heat used: HT = C*W*1000 (kcal)

Since 1 kcal = 4.2 kJ and kJ/s = kW,

Theoretical generation capacity: PT = 4.2*C*W*1000/3600 (kWh)

¥ç = 100*(3600/4200)*P/(C*W) = 85.7*P/(C*W)

If K = 85.7,

¥ç = K*P/(C*W)

*** Âü°í¹®Çå[References] ***

¥ç = K*P/(C*W)
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