Architecture
°ÇÃà Architecture


The force that pulls an object connected to two springs

ÀÛ¼ºÀÚ Uploader : doturak ÀÛ¼ºÀÏ Upload Date: 2023-07-05º¯°æÀÏ Update Date: 2023-07-05Á¶È¸¼ö View : 90

As shown in the figure, find the force F (N) required to stretch an object connected to two springs of length L (m) and spring constant of k (N/m) by x (m).
The object lies on a frictionless plane, the initial position is x=0, and the force acting on the spring is Fs=0.

Length of spring stretched

dL = sqr(L^2+x^2)-L

the force acting on the spring

Fs = k*dL = k*(sqr(L^2+x^2)-L)

Force in the x direction of Fs

Fsx = Fs*x/(L+dL) = k*(sqr(L^2+x^2)-L)*x/sqr(L^2+x^2)

Since there are two springs,

F = 2*Fsx = 2*k*(sqr(L^2+x^2)-L)*x/sqr(L^2+x^2)


*** Âü°í¹®Çå[References] ***

F = 2*k*(sqr(L^2+x^2)-L)*x/sqr(L^2+x^2)
º¯¼ö¸í Variable º¯¼ö°ª Value º¯ ¼ö ¼³ ¸í Description of the variable


¡Ø ÀÌ »çÀÌÆ®´Â ±¤°í¼öÀÍÀ¸·Î ¿î¿µµË´Ï´Ù.

¡Ú ·Î±×ÀÎ ÈÄ ¼ö½ÄÀÛ¼º ¹× Áñ°Üã±â¿¡ Ãß°¡ÇÒ ¼ö ÀÖ½À´Ï´Ù.
¡Ú To make new formula or to add this formula in your bookmark, log on please.


ÄÚ¸àÆ®

´ñ±Û ÀÔ·Â