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Projectile motion - Calculating the flight time using the maximum height

작성자 Uploader : tikitaka 작성일 Upload Date: 2023-07-14변경일 Update Date: 2023-07-14조회수 View : 92

As shown in the figure, for an object launched at height y0 (m), initial velocity V (m/s), and angle θ (degrees) made with the horizontal, when the maximum height ht (m) is given, the flight time ts (s) can be calculated.

The vertical velocity Vy of the object is 0 at ht, the vertical acceleration is -g, and the time t1(s) taken from y0 to ht is equal to the time taken from ht to y0 by free fall.

ht-y0 = (1/2)g*t1^2

t1 = sqr(2*(ht-y0)/g)

The time to reach from ht to the bottom is,

t2 = sqr(2*ht/g)

Thus,

ts = t1+t2 = sqr(2*(ht-y0)/g) + sqr(2*ht/g)

When y0 = 0, ts = 2*sqr(2*ht/g).

*** 참고문헌[References] ***

ts = sqr(2*(ht-y0)/g) + sqr(2*ht/g)


변수명 Variable	변수값 Value	변 수 설 명 Description of the variable

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Projectile motion - Calculating the flight time using the maximum height

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